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Retrograde Chess Answers
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| Colour | Piece | Excluded |
| Black | Pawn | Statement 4 |
| Black | Queen | Statement 5 |
| Black | Bishop (White squares) | Statement 6 |
| Black | Bishop (Black squares) | Statement 2 |
| Black | Rook | Statement 5 |
| Black | Rook | Statement 5 |
| White | Pawn | Statement 4 |
| White | Queen | Statement 7, 8 & 9 |
| White | Bishop (White squares) | Statement 7, 8 & 9 |
| White | Bishop (Black squares) | |
| White | Knight | Statement 7, 8 & 9 |
| White | Knight | Statement 7, 8 & 9 |
| White | Rook | Statement 7, 8 & 9 |
Item |
Statement | Conclusion |
| Get orientated | ||
1 |
The black pawn showing an apparent check could not have moved there as the black king is already in check | The black king is in check |
2 |
The black bishop cannot have moved and is missing | It must have been taken by white |
| Explain the position | ||
3 |
The black king must have had a piece between it and the white rook that is not there now | This must be a white pawn as the black pawn can be accounted for. |
4 |
The white pawn that was on C7 must have taken a black piece for promotion. It cannot be a black queen or rook as they would hold white in check. It cannot be a bishop as this is accounted for in statement 2. This must be a knight. | The black pawn must have been promoted to a knight. (It can be seen dawdling around the bottom of the board) |
| Remove Black | ||
5 |
Neither the black queen or rooks could be at the nominated square as they would place the white king in check | They can be excluded from candidate list |
6 |
The remaining black bishop is playing on white squares. The missing piece is playing black squares | It can be excluded from candidate list |
| Remove White | ||
7 |
The black pawn on A6 must have taken a white piece on a white square | One white piece on white square excluded |
8 |
The black pawn on C4 must have taken three white pieces on white squares | Three white pieces on white squares excluded |
9 |
The black pawn that converted could either have taken one piece to get through to G1 or two pieces to F1. Given that 5 white pieces are looking to be accounted for and four already have, the black pawn must have taken a white piece on G2. | One white piece on white square excluded |
| Conclusion | ||
10 |
The White bishop must be the remaining piece as it’s the only white piece that can never go on white squares | Result! |
11 |
This is a terrible game | They cant play chess |
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